# What is my percent to goal?

Finds how far along you are toward a goal as a percent: progress ÷ goal × 100, with the amount still left, or how far past the goal you are.

- Page: https://www.acalculator.org/math/percentage-to-goal
- JSON spec: https://www.acalculator.org/math/percentage-to-goal.json
- Version: 625f94c22bd5

## Default answer

Example with the default inputs (Progress so far 37,500, Goal 50,000): You are 75.00% of the way to your goal.

## Inputs

| Key | Label | Description |
| --- | --- | --- |
| p | Progress so far | What you have reached so far, such as sales, money saved or miles run. |
| g | Goal | The target, in the same units as the progress. |

## Outputs

| Key | Label | Description |
| --- | --- | --- |
| percent | Percent to goal | Progress ÷ goal × 100, to 2 decimal places. |
| left | Left to reach the goal | Goal − progress; 0 once the goal is reached. |
| leftPercent | Percent left | 100% minus the percent to goal; 0% once the goal is reached. |
| over | Past the goal by | Progress − goal, when the progress is above the goal. |

## Method

Percent to goal = progress ÷ goal × 100. Left = goal − progress (0 once reached); percent left = 100 − percent to goal (0 once reached); past the goal by = progress − goal.

## Assumptions

- Progress and goal are in the same units; the goal is above 0.
- Values are taken exactly as typed; the percents are rounded to 2 decimal places, halves away from zero.

## Worked examples

1. p = 37,500, g = 50,000 gives percent = 75.00%, left = 12,500, leftPercent = 25.00%. Source: OpenStax, Prealgebra 2e, §6.2 Solve General Applications of Percent (amount = percent × base, so percent = amount ÷ base), https://openstax.org/books/prealgebra-2e/pages/6-2-solve-general-applications-of-percent (retrieved 2026-10-05).
2. p = 2, g = 3 gives percent = 66.67%, left = 1, leftPercent = 33.33%. Source: OpenStax, Prealgebra 2e, §6.2 Solve General Applications of Percent (amount = percent × base, so percent = amount ÷ base), https://openstax.org/books/prealgebra-2e/pages/6-2-solve-general-applications-of-percent (retrieved 2026-10-05).
3. p = 130, g = 120 gives percent = 108.33%, left = 0, leftPercent = 0.00%, over = 10. Source: OpenStax, Prealgebra 2e, §6.2 Solve General Applications of Percent (amount = percent × base, so percent = amount ÷ base), https://openstax.org/books/prealgebra-2e/pages/6-2-solve-general-applications-of-percent (retrieved 2026-10-05).
4. p = 0.1, g = 0.8 gives percent = 12.50%, left = 0.7. Source: OpenStax, Prealgebra 2e, §6.2 Solve General Applications of Percent (amount = percent × base, so percent = amount ÷ base), https://openstax.org/books/prealgebra-2e/pages/6-2-solve-general-applications-of-percent (retrieved 2026-10-05).
5. p = 1, g = 8 gives percent = 12.50%, leftPercent = 87.50%. Source: OpenStax, Prealgebra 2e, §6.2 Solve General Applications of Percent (amount = percent × base, so percent = amount ÷ base), https://openstax.org/books/prealgebra-2e/pages/6-2-solve-general-applications-of-percent (retrieved 2026-10-05).

## FAQ

### How do I work out percent to goal?

Divide what you have done by the goal and multiply by 100. Sales of 37,500 against a 50,000 target are 37,500 ÷ 50,000 × 100 = 75% to goal.

### How much is left to reach my goal?

Subtract your progress from the goal: 50,000 − 37,500 = 12,500 left, which is 25% of the goal.

### Can I be more than 100% to goal?

Yes. 130 against a goal of 120 is 108.33% to goal, 10 past it.

### Does the unit matter?

No, as long as the progress and the goal use the same unit: dollars, units sold, miles, pounds lost or pages read.

### What if my progress is negative?

A loss gives a negative percent: −500 against a 2,000 goal is −25%, and 2,500 is left.

### How is it rounded?

The percents are shown to 2 decimal places, with a half rounded away from zero; the amount left keeps full precision.

## Sources

- OpenStax, Prealgebra 2e, §6.2 Solve General Applications of Percent: amount = percent × base, solved for the percent. CC BY 4.0. Retrieved 2026-10-05. https://openstax.org/books/prealgebra-2e/pages/6-2-solve-general-applications-of-percent
