What is the angular momentum?
How to calculate angular momentum: for a spinning body, type its moment of inertia and how fast it turns; for a point mass, type its mass, speed and distance. The angular momentum calculator gives L in kg·m²/s.
- Angular momentum (L), kg·m²/s
- 12.5664
The angular momentum is L = 12.5664 kg·m²/s.
- Angular velocity, rad/s
- 6.28319
- Angular velocity, rpm
- 60
- Rotational kinetic energy, J
- 39.4784
Angular momentum (L), kg·m²/s: 12.5664. The angular momentum is L = 12.5664 kg·m²/s.
How to calculate
Finds angular momentum L = I × ω for a spinning body, or L = r × m × v × sin θ for a point mass, in kg·m²/s, with the rotational kinetic energy or the linear momentum.
Example with the default inputs (For Spinning body (I and ω), Moment of inertia (I) 2, Inertia unit kg·m², Angular velocity (ω) 60, Turn rate unit rpm (rev/min)): The angular momentum is L = 12.5664 kg·m²/s.
Method: L = I × ω for a spinning body (rad/s), with K = ½Iω²; L = r × m × v × sin θ for a point mass, with p = m × v and lever arm r × sin θ.
- A spinning body turns about a fixed axis, and I is its moment of inertia about that axis.
- For a point mass, θ is the angle between the line from the point to the mass and the direction it moves; L is the size of r × p.
- Typed values are read as the exact decimals you typed; each result is rounded once to show.
Worked examples
Each example is checked against the calculator on every build.
- For Spinning body (I and ω), Moment of inertia (I) 1.67, Inertia unit kg·m², Angular velocity (ω) 3, Turn rate unit rpm (rev/min) gives Angular momentum (L), kg·m²/s 0.524646, Angular velocity, rad/s 0.314159, Angular velocity, rpm 3.Source: OpenStax, University Physics Volume 1, §11.2 Angular Momentum (Eq. 11.5 l = r × p, l = rp sin θ; Eq. 11.9 L = Iω; Example 11.6: a robot arm of I = 1.67 kg·m² turning at 0.1π rad/s has L = 0.17π kg·m²/s, and with a rock, I = 3.17 kg·m² and L = 0.32π kg·m²/s), https://openstax.org/books/university-physics-volume-1/pages/11-2-angular-momentum (retrieved 2026-10-19); OpenStax, University Physics Volume 1, §10.1 Rotational Variables (one revolution is 2π rad), https://openstax.org/books/university-physics-volume-1/pages/10-1-rotational-variables (retrieved 2026-10-19)
- For Spinning body (I and ω), Moment of inertia (I) 3.17, Inertia unit kg·m², Angular velocity (ω) 3, Turn rate unit rpm (rev/min) gives Angular momentum (L), kg·m²/s 0.995885.Source: OpenStax, University Physics Volume 1, §11.2 Angular Momentum (Eq. 11.5 l = r × p, l = rp sin θ; Eq. 11.9 L = Iω; Example 11.6: a robot arm of I = 1.67 kg·m² turning at 0.1π rad/s has L = 0.17π kg·m²/s, and with a rock, I = 3.17 kg·m² and L = 0.32π kg·m²/s), https://openstax.org/books/university-physics-volume-1/pages/11-2-angular-momentum (retrieved 2026-10-19)
- For Spinning body (I and ω), Moment of inertia (I) 2, Inertia unit kg·m², Angular velocity (ω) 10, Turn rate unit rad/s gives Angular momentum (L), kg·m²/s 20, Rotational kinetic energy, J 100, Angular velocity, rpm 95.493.Source: OpenStax, University Physics Volume 1, §11.2 Angular Momentum (Eq. 11.5 l = r × p, l = rp sin θ; Eq. 11.9 L = Iω; Example 11.6: a robot arm of I = 1.67 kg·m² turning at 0.1π rad/s has L = 0.17π kg·m²/s, and with a rock, I = 3.17 kg·m² and L = 0.32π kg·m²/s), https://openstax.org/books/university-physics-volume-1/pages/11-2-angular-momentum (retrieved 2026-10-19); OpenStax, University Physics Volume 1, §10.4 Moment of Inertia and Rotational Kinetic Energy (K = ½Iω², Eq. 10.17), https://openstax.org/books/university-physics-volume-1/pages/10-4-moment-of-inertia-and-rotational-kinetic-energy (retrieved 2026-10-19)
- For Point mass (m, v, r), Mass (m) 4.409 lb, Speed (v) 6.711 mph, Distance from the point (r) 13.12 ft, Angle between r and v (θ), degrees 90 gives Angular momentum (L), kg·m²/s 24, Linear momentum (p), kg·m/s 6, Lever arm (r sin θ), m 4.Source: OpenStax, University Physics Volume 1, §11.2 Angular Momentum (Eq. 11.5 l = r × p, l = rp sin θ; Eq. 11.9 L = Iω; Example 11.6: a robot arm of I = 1.67 kg·m² turning at 0.1π rad/s has L = 0.17π kg·m²/s, and with a rock, I = 3.17 kg·m² and L = 0.32π kg·m²/s), https://openstax.org/books/university-physics-volume-1/pages/11-2-angular-momentum (retrieved 2026-10-19)
- For Point mass (m, v, r), Mass (m) 4.409 lb, Speed (v) 6.711 mph, Distance from the point (r) 13.12 ft, Angle between r and v (θ), degrees 30 gives Angular momentum (L), kg·m²/s 12, Lever arm (r sin θ), m 2.Source: OpenStax, University Physics Volume 1, §11.2 Angular Momentum (Eq. 11.5 l = r × p, l = rp sin θ; Eq. 11.9 L = Iω; Example 11.6: a robot arm of I = 1.67 kg·m² turning at 0.1π rad/s has L = 0.17π kg·m²/s, and with a rock, I = 3.17 kg·m² and L = 0.32π kg·m²/s), https://openstax.org/books/university-physics-volume-1/pages/11-2-angular-momentum (retrieved 2026-10-19)
- For Spinning body (I and ω), Moment of inertia (I) 1, Inertia unit lb·ft², Angular velocity (ω) 1, Turn rate unit rad/s gives Angular momentum (L), kg·m²/s 0.0421401.Source: OpenStax, University Physics Volume 1, §11.2 Angular Momentum (Eq. 11.5 l = r × p, l = rp sin θ; Eq. 11.9 L = Iω; Example 11.6: a robot arm of I = 1.67 kg·m² turning at 0.1π rad/s has L = 0.17π kg·m²/s, and with a rock, I = 3.17 kg·m² and L = 0.32π kg·m²/s), https://openstax.org/books/university-physics-volume-1/pages/11-2-angular-momentum (retrieved 2026-10-19); NIST Special Publication 811, Appendix B.8 (1 lb = 0.45359237 kg, 1 ft² = 0.09290304 m²), https://www.nist.gov/pml/special-publication-811/nist-guide-si-appendix-b-conversion-factors/nist-guide-si-appendix-b8 (retrieved 2026-10-19)
How it works
Choose what turns:
- Spinning body (I and ω): a rigid body turning about a fixed axis has angular momentum L = I × ω (OpenStax Eq. 11.9), with I its moment of inertia about the axis in kg·m² and ω its angular velocity in rad/s. The page also shows ω in rad/s and in rpm (ω × 60 ÷ 2π), and the rotational kinetic energy K = ½ × I × ω² in J.
- Point mass (m, v, r): a mass m moving at speed v, at distance r from the point, has angular momentum l = r × p about that point (Eq. 11.5), of size L = r × m × v × sin θ, where θ is the angle between the line from the point to the mass and the direction it moves (90° for motion around a circle). The page also shows the linear momentum p = m × v in kg·m/s and the lever arm r × sin θ in m.
L is in kg·m²/s. The page gives its size; its direction is along the axis (right-hand rule).
Units (exact): moment of inertia 1 g·cm² = 10⁻⁷ kg·m²; 1 lb·ft² = 0.45359237 × 0.09290304 kg·m²; 1 lb·in² = 0.45359237 × 0.00064516 kg·m². Turn rates: 1 rpm = 2π ÷ 60 = π/30 rad/s; 1 rev/s = 2π rad/s; 1 °/s = π/180 rad/s. 1 g = 0.001 kg; 1 lb = 0.45359237 kg; 1 oz = 0.028349523125 kg; 1 km/h = 5/18 m/s; 1 mph = 0.44704 m/s; 1 ft/s = 0.3048 m/s; 1 mm = 0.001 m; 1 cm = 0.01 m; 1 in = 0.0254 m; 1 ft = 0.3048 m.
Rules
- Moment of inertia from 10⁻¹² to 10⁴⁰ and angular velocity from 10⁻¹² to 10¹², in the units chosen beside them.
- Mass from 10⁻¹² kg to 10³⁰ kg; speed from 10⁻¹² m/s to 3 × 10⁸ m/s; distance from 10⁻¹² m to 10¹⁵ m; θ from 0° to 180°. These limits are in SI units and include their ends; a value typed in another unit is converted first.
- At θ = 0° or 180° the mass moves straight toward or away from the point, so L = 0 and the lever arm is 0.
- A result too large or too small to show as a number gives no answer.
Output format
Every number shows to 6 significant figures, rounded half up, with trailing zeros dropped, thousands commas, and from 10¹⁵ up or below 10⁻⁶ as a × 10ⁿ. Typed values are read back as the exact decimals you typed, and every unit size is an exact fraction times a power of π, so each result is exact until one power of π is applied (a turn rate in rpm, rev/s or °/s brings π in). sin θ is exact where it is rational (0°, 30°, 90°, 150°, 180°); at other angles it is a 64-bit float. A result that is exactly 0 shows as 0.
The answer sentence reads The angular momentum is L = L kg·m²/s., with L written as its output is.
Worked examples by hand
A robot arm (OpenStax Example 11.6). I = 1.67 kg·m², turning at 3 rpm = 3 × π/30 = 0.1π rad/s = 0.314159 rad/s: L = 1.67 × 0.1π = 0.167π = 0.524646 kg·m²/s, the 0.17π of the example. Holding the rock, I = 3.17 kg·m² and L = 0.317π = 0.995885 kg·m²/s (0.32π).
A wheel. I = 2 kg·m² at 10 rad/s: L = 2 × 10 = 20 kg·m²/s, K = ½ × 2 × 10² = 100 J, and ω = 10 × 60 ÷ 2π = 95.493 rpm.
A point mass. m = 2 kg at v = 3 m/s, r = 4 m from the point, moving at θ = 90°: p = 2 × 3 = 6 kg·m/s, lever arm 4 × sin 90° = 4 m, L = 24 kg·m²/s. At θ = 30°, sin 30° = ½, so the lever arm is 2 m and L = 12 kg·m²/s.
US units. I = 1 lb·ft² at 1 rad/s: L = 0.45359237 × 0.09290304 × 1 = 0.0421401 kg·m²/s.
Other questions people ask
How do you calculate angular momentum?
For a body spinning about a fixed axis, multiply the moment of inertia by the angular velocity in rad/s: L = I × ω. A 2 kg·m² wheel at 10 rad/s has L = 20 kg·m²/s. For a point mass, L = r × m × v × sin θ.
What is the angular momentum formula for a particle?
l = r × p, a cross product, with size l = r × p × sin θ, where p = m × v and θ is the angle between r and the motion (OpenStax Eq. 11.5). A 2 kg mass at 3 m/s, 4 m from the point and moving at 90°, has l = 4 × 6 × 1 = 24 kg·m²/s.
What are the units of angular momentum?
Kilogram metres squared per second, kg·m²/s, which is the same as a joule second (J·s): a moment of inertia (kg·m²) times an angular velocity (1/s).
How do I use rpm in the angular momentum formula?
Turn rpm into rad/s first: one turn is 2π rad, so 1 rpm = 2π ÷ 60 = π/30 rad/s. The robot arm of OpenStax Example 11.6 turns at 3 rpm (0.1π rad/s) with I = 1.67 kg·m², so L = 0.167π = 0.525 kg·m²/s.
Is angular momentum conserved?
Yes, when no net external torque acts. A spinning skater who pulls in her arms lowers I, so ω rises to keep L = Iω the same.
What is the difference between angular momentum and rotational kinetic energy?
L = Iω grows with ω, while K = ½Iω² grows with ω². The page shows both for a spinning body: 2 kg·m² at 10 rad/s has L = 20 kg·m²/s and K = 100 J.